Question
Suppose $V$ and $W$ are finite-dimensional, $T \in \mathcal{L}(V, W),$ and there exists $\varphi \in V^{\prime}$ such that range $T^{\prime}=\operatorname{span}(\varphi) .$ Prove that null $T=$ null $\varphi$.
Step 1
We have a linear transformation \( T: V \rightarrow W \) and a linear functional \( \varphi \in V' \) (the dual space of \( V \)), such that the range of the dual transformation \( T' \) is the span of \( \varphi \). Recall that \( T' \) is a map from \( W' \) to Show more…
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