Suppose $v_{1}, \ldots, v_{n}$ is a basis of $V .$ Prove that the map $T: V \rightarrow \mathbf{F}^{n, 1}$ defined by
\[
T v=\mathcal{M}(v)
\]
is an isomorphism of $V$ onto $\mathbf{F}^{n, 1}$; here $\mathcal{M}(v)$ is the matrix of $v \in V$ with respect to the basis $v_{1}, \ldots, v_{n}$.