00:02
Okay, for this problem, they say for each of these operations, we're going to start from the initialization at the top.
00:12
So they don't affect the other lines.
00:15
And while they want us to determine the values of x, y, z at the end, well, it looks like x doesn't change here, and it's going to be 2 .5.
00:23
Let's see, y is going to be incremented, so it's going to be 7 .9, but that's a post, so after the modulo.
00:30
And we're going to multiply that result to z, and we're just going to end up.
00:33
With, let's see, 69.
00:39
And now we're going to assign x to something, but let's see, y and z will never change.
00:44
So there's still going to be 10 and 6 .9, well, 10 .0, but get the idea.
00:54
Let's see.
00:56
So we're going to cast y as an integer, so we're going to truncate, and let's see, z divided by 7, that'll go in once.
01:04
And in the end, when we assign to x, we're going to end up with 18 point let's see actually that's truncated so 18 works just fine let's see because that's 6 plus 13 is it okay and now part c looks like we're going to be decimating y but z is going to be kept the same so in this case our z is still 10 but our y is decremented by 1 to be 5 .9 and when we evaluate this expression, let's see, that's going to be a pre -decrement, so it's going to be decremented in that input.
02:02
But we're going to have for our x value as 19.
02:08
Let's see, 0 .6.
02:17
And let's see, over here, x and y will remain the same...