00:01
Hey, it's clarissa enumerate here.
00:02
So we're given f of x, comma, y is equal to 1 ,000 minus 0 .005 x squared minus 0 .001y square, and p is equal to 60, 40.
00:15
So we have to find the directional derivative of the function f at point p along v.
00:22
So using equation 9, we know that the directional derivative is this formula.
00:42
Times where u represents a unit vector in the direction of fee so we know that u is going to be equal to 1 over 1 0 comma negative 1 and the gradient of f is given by this formula is comma x comma and fx is equal to negative 0 .01x, and fy, x, x, comma, y, is equal to negative 0 .2y.
01:58
After we substitute the values of point p, we get negative 0 .6 ,000, 0 .8.
02:23
And from equation 9, we can write 60, 40 is equal to 0 .8.
02:43
This is after we simplify.
02:46
So since it's bigger than zero, we're going to move uphill as we move south.
02:51
So our answer is a walk to south from 60, 40, 966, is uphill at a rate of 0 .8 meters.
03:03
0 .8 meters, 0 .8 meters, yeah.
03:07
So for part b, we're given the same equation and we're going to find the directional derivative again.
03:21
So using equation 9, you find u, which is 1 over square root 2, negative 1, 1, 1.
03:33
The gradient is still this formula...