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Suppose you are using total internal reflection to make an efficient corner reflector. If there is air outside and the incident angle is $45.0^{\circ},$ what must be the minimum index of refraction of the material from which the reflector is made?
1.41
Physics 103
Chapter 25
Geometric Optics
Reflection and Refraction of Light
University of Washington
Simon Fraser University
University of Sheffield
University of Winnipeg
Lectures
02:30
In optics, ray optics is a…
10:00
In optics, reflection is t…
01:05
A light ray is incident no…
01:55
A 45$^\circ$$-$45$^\circ$$…
0:00
Find the minimum refractiv…
01:32
$\bullet$$\bullet \mathrm{…
07:38
Total Internal Reflection<…
02:12
$\bullet$$\bullet$ A ray o…
01:06
A plastic light pipe has a…
03:39
A beam of light is traveli…
01:17
The angle of incidence of …
02:26
What is the index of refra…
04:11
Additional ProblemsIn …
01:41
A block of glass has a cri…
01:12
Light incident on a $45.0^…
Light in air is incident u…
09:10
01:36
A ray of light is incident…
01:30
01:02
A fiber-optic rod consists…
03:16
A fiber-optic cable used f…
maximum of perfecting next for the material for ah critical angle over 45. Um, he's given by the relation that is a sign off. A critical angle particularly is cool. Thio is it cool to refractive index off air derided by refractive index over material. So, uh, then solving for refractive index of the deal that is equal to a tractor. Next off air is one divided by sign off 45 45 And, uh, simplifying this expression gives us refracting tips. Off material is one point for 14 End off the problem. Thank you for watching.
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