00:01
So here we know that for this case, the sum of forces in the wide direction equals zero.
00:07
And we then know that the weight is equaling mg, and this would be equal to the normal force.
00:12
And so the normal force would be equaling the weight of 120 kilograms multiplied by 9 .8 meters per second squared.
00:21
This is giving us 1 ,176 neutrons.
00:24
And so the force of friction for part a would be equaling the coefficient of static friction.
00:30
Times the normal force.
00:32
This would be equal to 0 .5 multiplied by 1 ,176 newtons and so the force of friction is equaling 588 newtons.
00:43
This would be our answer for part a.
00:46
For part b now the coefficient of for part b now we know that the coefficient of friction will be dynamic coefficient of friction.
00:55
So here the mass of the crate remains the same and we have that the force of friction is equaling the coefficient of kinetic friction times the force normal...