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Suppose you stand with one foot on ceramic flooring and one foot on a wool carpet, making contact over an area of 80.0 ${cm}^{2}$2 with each foot. Both the ceramic and the carpet are 2.00 cm thick and are $10.0^{\circ} {C}$on their bottom sides. At what rate must heat transfer occur from each foot to keep the top of the ceramic and carpet at $33.0^{\circ} {C}$ ?

The rate of heat transfer is 0.368 $\mathrm{W}$ for the leg in contact with the carpet,while it is 7.73 $\mathrm{W}$ for the leg in contact with the ceramic.

Physics 101 Mechanics

Chapter 14

Heat and Heat Transfer Methods

Thermal Properties of Matter

University of Michigan - Ann Arbor

Hope College

University of Sheffield

University of Winnipeg

Lectures

02:20

A solid, liquid, or gas is…

06:13

Matter is a state of aggre…

03:09

Suppose you stand with one…

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For a temperature differen…

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Find the rate of conductio…

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(a) Calculate the rate of …

03:48

(a) What is the rate of he…

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03:29

Suppose you walk into a sa…

00:17

Hot air at $80^{\circ} \m…

02:37

Find the heat-loss rate th…

01:43

Suppose a person is covere…

03:43

The top of a steel wood st…

08:43

A carpenter builds an exte…

01:58

A cubical piece of heat-sh…

07:02

\bullet A carpenter builds…

02:49

$\cdot$ A slab of a therma…

05:15

01:05

A person's body is co…

04:30

Compare the rate of heat c…

06:07

A black wood stove with su…

01:13

For heat transfer purpos…

just all this question. We're going to use the formula off. Heat transfer is equal to K, the constant off it transfer for each material area. Difference in the temperature on divided by the thickness of that off the material. So this formula we are going to use twice for once forward and once for the ceramic. So let's do for one so forward. Q. Divided by teeth is equal to value of Capable is very small, which is 0.4 area is given us. It is intimate a square, so we must multiply it by 10 power negative for to make it in terms off meter square. Difference in the temperature is 33 minus 10 which is 23 remember that it's the difference so we can keep it in terms of degree Celsius. Onda thickness is to send to Mito, so that means two times 10 power negative, too. So if you do this calculation, you will get 0.368 What now? Let's do the same calculation for syrup IQ. It gives you Q divided by T equals K a Delta T. What about it by D so Valley of K for serum IQ is from the textbook. Well, let's will take a value. Jizz 0.84 times area is again the same as, uh, we had for the wool carpet 80 times 10 hours getting four times difference in temperature is same and the thickness is also same, which is two centimeter. So if you do this calculation, you will get Answer is 7.73 report. So the heat transfer from the for the leg in contact with the carpet should be 0.368 What? On the leg? In contact with the serum IQ, the heat transfer must be 7.70 watts, but thank you.

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