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Suppose you walk into a sauna that has an ambient temperature of $50.0^{\circ} {C}$ . (a) Calculate the rate of heat transfer to you by radiation given your skin temperature is $37.0^{\circ} \mathrm{C}$ , the emissivity of skin is 0.98, and the surface area of your body is 1.50 $\mathrm{m}^{2}$. (b) If all other forms of heat transfer are balanced (the net heat transfer is zero), at what rate will your body temperature increase if your mass is 75.0 kg?

$\Delta T=5.2 * 10^{-4} \mathrm{c} / \mathrm{s}$

Physics 101 Mechanics

Chapter 14

Heat and Heat Transfer Methods

Thermal Properties of Matter

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

University of Sheffield

Lectures

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in number 60. Um, we're in a sauna that has a temperature of 50 degrees Celsius, and the temperature of your skin is 37 degree Celsius. We're giving the M acidity of skin. We're given the area of skin and were testifying. What is the rate of heat transfer? I remember T two is the temperature of the environment. So this is the tea to this would be the tee wanting the skin. Oh, and remember to go in these equations. Those have to be in Kelvin. That's Celsius. So I'm gonna add the 2 73 to both of those got ready to plug into my equation here for I'm looking for the rate. Well, this is bolts mons constant. That's always the same. 5.67 times 10 to the negative Eighth. I was given the impulsivity of the skin 0.98. I was given the area of the skin 1.5 at t two. When I changed it to him, Kelvin was 3 23 tickets to the fourth power and to you one. When I changed it, it was three. Ton also praised the fourth hour. I just multiply. I subtract and multiply, and I get 137. That would be Jules per second or Watts. That's a positive number because it's going of. The skin is cooler than the sauna, and then they're asking if all of that heat, all that power was used to raise the temperature. How much does the temperature of Ray's? What is the rate at which the temperature raises? Well, I know that if I'm just there's no face change. So the heat I'm see Delta two it just gives me a temperature change. Andi, I know if this is 137 watts, it's 137 jewels every second, so I'm just gonna figure this out for one second. So if my heat will be 1 37 I was given that the master, the person's 75 kilograms, a specific heat. I just looked at the specific heat of the human body on table 14.1. I picked the one that was in jewels per kilogram degree Celsius, and that was 3500. I'm trying to find the change in temperature. I divide like my change in temperature was quaint. Um 000 5 to 2, Um, small number like that. I might put that in scientific notation. Remember, I was justifying the rate and I did this for one second. So this would be this every second, so I could see my rate of temperature change would be by 0.22 times 10 to the negative forth degree Celsius per second.

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