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Suppose your 50.0 $\mathrm{mm}$ focal length camera lens is 51.0 $\mathrm{mm}$ away from the film in the camera. (a) How far away is an object that is in focus? (b) What is the height of the object ifits image is 2.00 $\mathrm{cm}$ high?

a) 2.55 $\mathrm{m}$b) 1.00 $\mathrm{m}$

Physics 103

Chapter 25

Geometric Optics

Reflection and Refraction of Light

Cornell University

Rutgers, The State University of New Jersey

Simon Fraser University

Lectures

02:30

In optics, ray optics is a…

10:00

In optics, reflection is t…

01:25

For a camera equipped with…

01:53

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A lens for a digital camer…

02:22

Camera lenses are describe…

02:24

(II) For a camera equipped…

02:33

You photograph a 2.0-m-ta…

02:14

Suppose a 200 $\mathrm{mm}…

03:13

A camera with a 50.0 $\mat…

00:26

The distance between an ob…

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02:52

(II) (a) How far from a 50…

01:27

A camera lens has a focal …

00:59

If an object is $10.0 \mat…

06:07

A camera lens has a fixed …

02:53

(II) $(a)$ How far from a …

05:25

(II) An 80 -mm-focal-lengt…

02:57

An object with a height of…

01:14

A camera lens used for tak…

01:47

A microscope has an object…

00:52

A camera with a 50.0 -mm l…

problem. Number of 46 point A, um, the distance to object is given by using it. This ta lens formula, which is one word distance to object, is equal to one over focal length, minus one or distance to the image. Uh, focal length we have is a 50 where there is a distance toe image, given his age 51. Really? Me too. Then we can simplify this these fractions, and get there distance to an object, which is 25 five Uh oh, me. Amedure's three meters. Then in Bobby, we are asked to find the height often object. So hyde often object is given by, um, um height off the image height off the image divided by the magnification. So in order to find the height off object, we need to find a magnification so we can fight magnification using, um, the values that we have, which is the distance to image we have is a minus 5 51 divided by the distance the object, which is a 255 We found it about a then dividing these two numbers gives us a minus zero point zero to unification. Then we can substitute the value here on dhe, which will be the more off the medication so it will give us a poster number, then height offer images to divided by zero point to their concert to this gives us their height often object. I don't an object off 100 centimeter, 100 centimetres. End off the problem. Thank you for watching.

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