00:01
All right, so we're given a polynomial f, and we want to show that f has exactly one inflection point, and that it occurs at x equal to negative a over 3, and then show that f is an odd function with respect to this inflection point.
00:21
So we're given f of x equal x cubed plus a x squared, plus a x squared.
00:34
Plus bx plus c.
00:36
So to find points of inflection, we want to look at the second derivative and see where this is equal to zero.
00:43
So for our first derivative, we have 3x squared plus 2 a x, b.
00:54
For second derivative, we get 6x plus 2a.
01:01
So we know that this will be equal to 0 at only one value of x, since this is just x raised to the first so it's only going to be one point.
01:12
And then if we set this equal to 0, you get that x is equal to negative a over 3.
01:25
So that shows part a...