00:01
Let's outline the synthesis of each of the following, starting from diethylmalinate.
00:08
So for a, we need to do the synthesis of two methylbutanolic acid.
00:15
So starting from diethylmalinate, first reaction here would be an a, and also with ch3br.
00:55
This would produce e -t -o -t -b -o, double bond -o, the addition of a methyl group.
01:14
And then we would have e -t -o -n -a, e -t -o -h -3 -ch2 -b -r, and this would produce e -t -o, addition of a methyl group there.
01:57
And then we would have h3o plus and heat.
02:08
And this would yield 1 -2 -0h, double bond o here.
02:18
And this will be our product, which is 2 -methyl butenoic acid.
02:34
And this would be our product, 2 -methylbutanolic acid, starting from diethyl malinate.
02:45
For b, again, starting from diethylmalinate, we are to synthesize 4 -methyl -1 pentanol.
03:11
First step here.
03:16
E -t -o -n -a.
03:20
E -t -o -h, c -h -3 -2, c -h -h -c -h -h -2 -b -o -o.
03:31
And this would produce three four two three four and then we'd react this with h3 o plus in heat to produce double bond oh oh oh no oh sorry oet and methyl group there and then we'll react this further with lithium aluminum hydride.
04:48
This will produce...