00:01
This question wants us to find this line integral.
00:05
And we should check that it's conservative first, because that would make our lives a lot easier.
00:13
So we want to check that the y derivative of the x is the x derivative of the y, that the z derivative of the y is the y derivative of the z, and that the z derivative of the x is equal to the x derivative of the z.
00:32
So checking each of these conditions, the y derivative of the x is 0, the x derivative of the y is 0, so that works.
00:47
Then the z derivative of the y, we'd have to use the product rule on, so we'd get sine y z plus z cosine of y z times y.
01:12
And then for the y derivative of the z we'd get the same thing so that works then for the z derivative of the x we get zero and for the x derivative of the z we get zero so we do have a conservative field so that means f is the gradient of some potential so to find each piece of the potential we'll just integrate with each component with their respective variable.
01:56
So first we integrate x squared with respect to x to get x cubed over 3 plus some function depending on x and y, sorry y and z.
02:11
Then phi 2 we get the second piece by integrating z sine y z with respect to y z.
02:24
And then if we do this, we'd get negative cosine of yz divided by z, so just a negative cosine of yc, plus some function of x and z...