00:01
Here we have a simple circuit where the resistance r1 is in series with the resistance r2, and this will be crucial in our calculations.
00:09
So we're given the emf of the battery or the voltage as 12 volts, and we're given the resistance of r1 as 270 oms.
00:20
And part a wants to find the resistance in r2, given its voltage, which we'll call v2, is 4 .5 volts.
00:31
So we have to find first the current in this circuit.
00:36
And we know that the current going through r1 will be the same current going in through r2 because the resistors are in series.
00:47
So all we have to do is find the current going through r1 and we can use that information to find the resistance for r2.
00:55
So we use the equation, the emf for the voltage of the battery, is equal to the current times r1 so we solve for the current we have i is equal to the emf of the battery divided by r1 so now we plug in our numbers we have 12 divided by 270 and so the current going through the circuit is i is equal to 0 .0 4 amps and now we can use that to find r2.
01:36
So we know omn's law is given as v, or here v2 is equal to i times r2...