$$
\tan ^{-1} \frac{1}{5}+\tan ^{-1} \frac{1}{7}+\tan ^{-1} \frac{1}{3}+\tan ^{-1} \frac{1}{8}=\frac{\pi}{4}
$$

Answer

Related Courses

Calculus 1 / AB

NCERT Class 12 Part 1 - Math

Chapter 2

Inverse Trigonometric Functions

Section 3

Properties of Inverse Trigonometric Functions

Discussion

You must be signed in to discuss.

Top Calculus 1 / AB Educators

Watch More Solved Questions in Chapter 2

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Video Transcript

question we have to prove that 10 was won by five plus 10 and was won by seven plus. 10 was one by three. Last standing was one x 8. Essick was still by by four. Played in discussion, will be learning the concept of inverse Trina metric functions and its properties. So the approach to solve this question is Where do we call the formula of 10 verse six plus? Then it was white and we can play this formula to simplify your ledges late. So we can group the terms, we can take these first two terms and the last two times as a pair and we can apply the formula. So we get 10 and west one x 5 plus one x 7, Divided by one one x 5 into one x 7. Similarly then it was one x 3 plus one x 8, Divided by one one by three. Doing made right? So we are we are solving Alleges So when we simplify this, we get 10 and was six. Yeah by 17 plus standing was 11 x 23. Right now we can again apply the same formula for this For this pair of 10 was extended in this way. Right? So we get then it was six x 17 plus 11 x 23. one minor upon one -X, Y, XY means the multiplication of X and Y. Right. Mhm. When we simplify this we get the value of standing was one and we know that this is equal to by by foot, which is our largest. Hence Allegis is equal. Zoologist. They Yeah. Mhm.

Get More Help with this Textbook