Question
Tangent lines Find an equation of the line tangent to the curve at the point corresponding to the given value of $t.$$$x=t^{2}-1, y=t^{3}+t ; t=2$$
Step 1
This will give us the slope of the tangent line at any point $t$ on the curve. The derivative of $x$ with respect to $t$ is given by: $$\frac{dx}{dt} = 2t$$ The derivative of $y$ with respect to $t$ is given by: $$\frac{dy}{dt} = 3t^{2}+1$$ Show more…
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