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Problem 3 Easy Difficulty

Tell whether each situation is a permutation or combination.
How many ways can a 3 -player team be chosen from 9 students?

Answer

$\mathrm{C} ; 84$ ways

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Top Algebra Educators
Catherine R.

Missouri State University

Alayna H.

McMaster University

Kayleah T.

Harvey Mudd College

MG
Maria G.

Numerade Educator

Video Transcript

Okay, so I'm making a team, and it doesn't matter that order. My people are picked, Mike, a team. You're still a team of three, regardless of when you're picked. So this is gonna be a combination, um, where we have non to choose from, and we want to choose three of them. So that means that we have non for our first person eight for a 2nd 7 for third. But we also need to remember to take into account how those people are picked, because maybe we pick someone in first. But the next group, we also think them the third time was not a different group. So for combination, when the order is not important, take that second number. We're going to see how many ways it can be changed. And so that's where the three times, two times one comes in. So what this gives me is 270 about about six. And so there are 45 possible teams that I could create from a list of non where I chose three

University of Louisville
Top Algebra Educators
Catherine R.

Missouri State University

Alayna H.

McMaster University

Kayleah T.

Harvey Mudd College

MG
Maria G.

Numerade Educator