00:01
All right, so this question gives us the data for the sales at a tire store, given there are three locations, and the number of auto tires and truck tires that they sold in january, february, and march.
00:14
In part a of this question, we're asked to create a two -by -three sales matrix for each store.
00:21
So we have store c, store s, and store d, given the number of auto and truck tires they sold in january, february, in march.
00:33
So we are told that for store c, 350 auto tires are sold in january, 420 auto tires are sold in february, and 530 auto tires are sold in march.
00:51
So you can see i filled this in in the first row of our 2x3 matrix for auto tires.
00:55
And then each column is the number of tires that was sold in the corresponding month.
01:00
For truck tires at this store, we sold 220 in january, 180 in february, and 140 in march.
01:10
We're going to go ahead and repeat this process for store s.
01:14
So we are told in the question that 430 auto tires are sold in january.
01:19
So i felt that in row one, column one corresponding with auto and january.
01:25
560 auto tires were sold in february, and 690 auto tires were sold in march.
01:30
For truck tires, 280 were sold in january, 320 were sold in february, and 220 were sold in march.
01:42
Finally, for our last store, store d, 864 tires were sold in january for auto, 980 auto tires were sold in february, and 1236 were sold in march.
02:01
For truck tires, 535 are sold in january, 542 were sold in february, and 332 were sold in merch.
02:11
So this completes part a, where we had to create three 2x3 matrices using the given data for each store.
02:20
Now moving over to part b, we are asked the difference between the number of tires that the downtown store sold.
02:32
Store d versus the other two stores combined.
02:36
So to do so, i'm going to subtract the combined sales from stores c and s from store d.
02:46
So to tell the difference between d and the other two stores combined.
02:50
Again, we're going to create a two by three matrix to display this result.
02:56
But before i do this, i'm first just going to calculate the combined stores.
03:00
So matrix c plus s.
03:03
To do so, i just add corresponding components.
03:06
So row 1, column 1 of c plus row 2, row 1, column 1 of s is 350 plus 430, which gives us 780.
03:17
Column 2, 420 plus 560 gives me 980.
03:22
Column 3, 530 plus 690 gives me 1220.
03:27
Moving into the second row, 220 plus 280 is 500.
03:31
180 plus 320 is also 500, and 140 plus 220 is 360.
03:39
Now i'm going to find d minus this combined matrix.
03:44
So to find this matrix, we subtract corresponding components in c plus s, our combined matrix, from d.
03:55
In row 1, column 1, we would have 864 minus 780, which gives me 84, column 2, 90d minus 90d is 0.
04:07
Column 3, 1236 minus 1220 gives me 16...