00:01
Hello students in this question we have to find the binding energy per nucleon of neon 10 20 and iron 26 and 56 so we know that the binding energy it is equals to the jad multiplied by mass of the proton minus number of neutrons multiplied by mass of the neutron minus mass of the nucleus and multiplied by this c sphere so where for this atom neonononon 10, 20, we are solving for 8.
00:33
So z is equal to 10, which is this number, and number of neutrons it is equals to a minus z, so a is equals to 20, so 20 minus 10, it is equals to 10.
00:44
And mass of the proton, it is equals to 1 .007825 atomic mass unit, and mass of the neutron, it is equals to 1 .008 -65 atomic mass unit, okay? and this atomic mass unit 1u, it can be written as 931 .5 mega electron volt per c square.
01:08
Okay.
01:09
So after substituting these values, so these values after substituting the binding energy per nucleon and after dividing for the per nucleon, so by a it will be divided, okay? so after solving for this nucleus, the binding energy per nucleon for the neon, it will be obtained as 8 .6 double 8 mega electron volt.
01:34
So this become the answer for the binding energy.
01:37
Okay.
01:39
And now next for the neck nucleus, which is iron, 26, 56...