00:03
In this question, we are given 3 proton nmr spectra corresponding to 3 isomers with the molecular formula c4h9br.
00:20
And we are supposed to take a look at each spectrum and figure out which isomal it corresponds to.
00:28
So if we look at the spectrum a, we see that the most downfield signal, which is near 4 ppm, has an integral ratio of 1.
00:39
So for that to be true, the most likely structure or the part of the structure should be something like this.
00:54
A single proton attached to a carbon that is attached to the bromine in the molecule because the bromine is the only component in the molecule that can give rise to a downfield signal.
01:10
So that's what we learned from the most downfield signal.
01:16
And then if we take a look at the rest of the spectrum, we see that there are three more peaks that we need to account for that tells us.
01:26
There are three more types of hydrogens in this molecule.
01:30
And then we also have three more carbons to account for.
01:33
So out of the three types of hydrogens, we see that two of them are closer to each other in chemical shifts, while one of them has a more upfield chemical shift.
01:52
So for that to be true, the structure has to pretty much look like this.
02:03
So the two near signals will be coming from these three protons and these two protons.
02:10
Which are both pretty close to the bromine, while the most upfield signal will be coming from these three methyl protons, which are equivalent to each other.
02:20
So this is the structure corresponding to the spectrum a.
02:28
And then if we move on to the second spectrum, we see that the most downfield signal has an integral ratio of two.
02:37
So that should be coming from something like this...