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A 40 -lb ladder rests against a wall when the bot…

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Problem 118 Easy Difficulty

The 10 -lb-uniform rod $A B$ has a total length of $2 L=2 \mathrm{ft}$ and is attached to collars of negligible mass that slide without friction along fixed rods. If rod $A B$ is released from rest when $\theta=30^{\circ},$ determine immediately after release ( $a$ ) the angular acceleration of the rod,
$(b)$ the reaction at $A$


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Video Transcript

Hello. So, for this question, you want to find the angular acceleration and the reaction at a from problem. 117 The humble A celebration is given by that formula. So I'm gonna celebration is, uh, Alfa. He's given by G Jesus. Solution. Need to gravity. L is the length. Uh, we have some angles. So for the first part is gonna be substitution. Gs never had one. The length the length was given us 1 ft or 1 ft, so I converted that mirrors. Now I'll give you 0.305 the angle giving us 30 degrees. So do this calculation you get to your I'm gonna acceleration to be done. 27.58 Iraq with second squared there for the second part. So for the second party offender reaction and eight, this is the expression for finding the reaction at a So come here. Um, be must Must was given in pounds. So were converted. That 2 kg give me 4.54 times of gravity, divided by the angle of 30 degrees. So you do that you get the reaction at a 25.45 Richards. So that is that for this question. Thank you.

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