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The $^{14} \mathrm{C}$ isotope undergoes beta decay according to the process given by Equation 29.15. Find the Q value for this process.

0.156 \mathrm{MeV}

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Rutgers, The State University of New Jersey

Numerade Educator

University of Sheffield

McMaster University

the number 54. We want to find the Q value for the baby decay of carbon 14. So I'm gonna write my reaction first. That's a carbon 14 and no, carbon hasn't something. Number six, it's going to decay and give off beta particle. And whenever you give a for beta particle, you also have an Ansari neutrino on my other product. I can tell my mass doesn't change. That's 14. We're gonna have one more proton, so this is gonna be seven. What's to know if I'm gonna find a cute value? I just look up the masses of these back independence be, um, so Mrs Corbin 14 is 14.0, 3242 mess of this later. June this 14 point 003 074 missed. So Tony doesn't count, and this has no mess. So I'm just attracting these and I get my difference is 0.0! 168 Remember, these were mass is measuring atomic mass units. So that's a new And I'm just going to convert that to its energy equivalence. I know one. You is the same as 931 0.5 Mega Electron volts, So use cancel. And my answer is gonna be a point 156 mega electron volts. That'll be Q.

University of Virginia