00:02
We have weight of the collar, w equals to 3 pound and stiffness of the spring k equals to 4 pound per feet.
00:12
Okay, and the unstressed length of the spring, x not, is equal to 50 inch.
00:19
So now, using work energy theorem, we can write that u1 to dash, this will be equals to delta t plus delta vg plus delta ve.
00:29
This will be equal to 0.
00:30
So the initial kinetic energy, t .a will be equal to 0 because color has been released from the rest and tb will be equals to 1 by 2 m vb square.
00:43
Where vb is the speed of the caller when it reaches at point b.
00:47
So now taking initial position to the datum, we can write that vga equals to 0 and so vgb this will be equals to minus mgh and we have mg equals to.
01:00
To w and h is equal to 12 inch so 12 by 12 20 by 12 feet okay so now as an stress length of the spring is 50 inch so when caller is at position b the elongated length of the spring will become 36 square plus 60 square and whole under root this will become 60 .97 inch so in this condition the initial and final elastic spring potential energies will be a vea equals to 1 by 2k 40 minus 50 divided by 12 square and veb this will become 1 by 2k 69 .97 minus 50 divided by 12 square...
