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The 3 -lb uniform rod $B D$ is connected to crank $A B$ and to a collar of negligible weight. A couple (not shown) is applied to crank $A B$ causing it to rotate. At the instant shown, crank $A B$ has an angular velocity of $12 \mathrm{rad} / \mathrm{s}$ and an angular acceleration of $80 \mathrm{rad} / \mathrm{s}^{2} ;$ both are counterclockwise. Neglecting the effect of friction, determine the reaction at $D$

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Physics 101 Mechanics

Chapter 16

Plane Motion of Rigid Bodies: Forces and Accelerations

Section 2

Constrained Plane Motion

Motion Along a Straight Line

University of Michigan - Ann Arbor

University of Washington

University of Winnipeg

Lectures

04:34

In physics, kinematics is the description of the motion of objects and systems in the frame of reference defined by the observer. An observer has to be specified, otherwise the term is meaningless.

07:57

In mathematics, a position is a point in space. The concept is abstracted from physical space, in which a position is a location given by the coordinates of a point. In physics, the term is used to describe a family of quantities which describe the configuration of a physical system in a given state. The term is also used to describe the set of possible configurations of a system.

16:20

The 3 -lb uniform rod $B D…

18:51

11:21

The $4-\mathrm{kg}$ unifor…

11:57

The 4 -lb uniform slender …

Hello Friends as cylinder figure a rod beauty off with three point connected to the crank Heavy on quality. If moment is given toe the grant heavy so that that having angular velocity off 12 radian per second on angular acceleration off eight Iranian per second squared both in counter clock direction. At that instant, calculate the reaction at ITI. Let's discuss that I never takes up. Drink a B. This is it. This is the AL five A period in per second square a V normal acceleration at the 10 nation mhm writing the value off normal intend intel acceleration off the point The normal acceleration off we point will be Omega Square are this length is given three inch omega is given Well, the club is squared in tow three white 12 So it would be 36 54 2nd square on 10 Usual acceleration is and find to art 80 into three y 12. It would be 2050 per second squared No kinda Matics off the road. BD Thank you All right Violence city off the well the city off the instantaneous center When we govt this will be off six inch Yeah, the velocity off we will be omega a V into every the velocity off the you will get three y 12 and 12 3 ft per second. Angular velocity off the tee. Better city off the upon B C three upon 30.5 six. Radiant per second. Yeah, right. No exploration. If we discuss mhm at any point, there will be normal acceleration. There will be attending initial acceleration at a D point there. Well, we are an initial acceleration. There will be a normal acceleration. This is the center of mass, but duty on Omega Beauty so we can write eighties culture, right? A B plus acceleration off. Be with respect. Toby. 80 is in downward direction. Our direction 20 towards left, right. Sorry. Yes. 36 inches off the direction A TV 345 This is normal. Can you? Mhm. Uh huh. Acceleration off the with respect, Toby, in normal direction is 30 ft per second square on acceleration. Off the with respect Toby intern initial direction and by 12 Al poverty putting any question? But a D yeah. Maybe continue towards right. 36 inches upper direction. A D be normal. 30 in this direction. The stand by 12 and poverty 345 If we take the X component off this equation country minus four by five into 30 three ways Fights in tow. 10 by 12 Al poverty must be zero So alphabet from this equation, we will get eight radiant per second square in contract, blocked by direction now acceleration off eight. Can we define this? Expiration of center Off off the road BD Acceleration off B plus acceleration off the with respect Toby baby bless half off a Levi Substituting develop Compute towards right 36 Alert half off 30 in that direction 345 Oh, and by 12 toe eat four way 35 All right, so it's X component. We will get 20 believes for by five until 15 three by five and 3.333 it will be 10 50 per second squared. Similarly, by component off it 36 355 to 50 plus 4 +55 and 3.333 It would be 47 point 67 50 per second squared. So this is towards right and this is a bird direction Now during the free body diagram off road ready toe find the reaction at D. This is the point. Be right. The X. This is Reaction D. This is the center off muscle here. The weight off the road village I m a X. But I am a Beiber and I am 12 Moment off inertia off the road about the center off my husband by 12 and many script. Wait is three three Baiji lent it 10 by 12 ft, so it would be 0.17 361 Upon the calculating the couple about Bobby points, it would be the in tow. This is six. So be in 26 Why 12 for white 12. I've are into help. I am a by three y 12. I am eight x m a y well, right through it so it can be treated as 0.5 and to be bait is given three and one by three. I have calculated 0.17 361 divided by G And to hell for it to you by G 10 in tow, one by food, everybody 4.767 into one by three. So value off the by solving the every question 5.15 point. What's right? That is the answer for this problem. Thanks for watching it

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