00:01
Hello friends as shown in the figure rod vd of weight 3 pound connected to the crank av and caller d.
00:11
If moment is given to the crank av so that it having angular velocity of 12 radian per second and angular acceleration of 80 radian per second square both in counter clock by direction at that instant calculate the reaction at d.
00:34
Let discuss the kinematics of crank av this is a this is the alpha a v 80 radial per second is square a v normal acceleration at the tension i think the value of normal and tangential acceleration of v point the normal acceleration of v point will be omega square are this length is given 3 inch omega is given 12 so 12 square into 3 by 12 so it would be 36 fit per second square and tangential acceleration is alpha into r 80 into 3 by 12 so it would be 20 fit per second square now kinematics of the rod vd, velocity of v, velocity of d, instantaneous center, omega vd, this will be of 6 inch.
04:25
The velocity of v will be omega av into av.
04:36
So velocity of v you will get 3 by 12 into 12, 3 fit per second.
04:44
So angular velocity of vd, velocity of b upon bc, 3 upon 0 .5, 6 radian per second.
05:08
Now acceleration, if we discuss at b point, there will be normal acceleration, there will be a tangential acceleration.
05:27
At d point there will be a tangential acceleration.
05:38
There will be a normal acceleration.
05:55
This is the center of mass, alpha v .d and omega v .d.
06:16
So we can write ad is equal to ab plus acceleration of d with respect to b.
06:30
So ad is in downward direction or upper direction...