Let the point on the curve be $(x_1, y_1)$. Then, we have $\sqrt{x_1 y_1} = a + x_1$. Differentiating both sides with respect to $x$, we get:
$\frac{1}{2} \frac{y_1 + x_1}{\sqrt{x_1 y_1}} \frac{dy}{dx} = 1$
Now, we can find the slope of the tangent line at
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