00:01
Question 48 is based on the data shown in this table, which i got in the textbook.
00:05
It measures the activity of the sample over a period of 12 hours.
00:10
Part a, the question asks to plot the logarithm of the counting rate as a function of the time in hours.
00:15
So i did that in excel.
00:18
I went ahead and i posted here.
00:20
So here we see a relatively straight line.
00:24
Or x -axis, of course, time.
00:28
Sorry, our x -axis is of course time.
00:31
And on our y -axis, we have the natural logarithm of our.
00:34
Counting rate our activity.
00:39
So that means if we have something where we have our activity is our initial activity times our exponential decay by plotting the natural logarithm of this ratio, so r over r not, and then take the natural logarithm of both signs.
00:54
You see here we're plotting on our x -axis.
00:57
It's dependent on two terms, i guess just one, sorry, lambda the decay constant.
01:03
So that means because it's a straight line, the slope of this line would be equivalent to the decay constant, which is pretty useful, actually, and especially in part b, it asks us to determine this decay constant and half -life, where i did this already in excel, i use the graving function to determine what this would be.
01:23
So again, based on this function, that the slope, our decay constant is the slope, and of course, it's negative.
01:30
So the decay concept itself would not be negative, it's just the slope itself has be negative.
01:36
Because our x -axis is in units of hours, then the units for the key constant have to be one over hours.
01:43
Great, and then all it's due to solve for half -life is just take the natural logarithm of 2 and divide that by lambda...