Question
The activity of a sample containing radioactive ${ }^{108} \mathrm{Ag}$ is $6.4 \times 10^{4}$ Bq. Exactly 12 min later, the activity is $2.0 \times$ $10^{3}$ Bq. Calculate the half-life of ${ }^{108} \mathrm{Ag}$.
Step 1
First, we need to find the decay constant λ. We can use the formula for activity: A = A₀ * e^(-λt), where A is the final activity, A₀ is the initial activity, and t is the time elapsed. Show more…
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The activity of a sample containing radioactive $^{108} \mathrm{Ag}$ is $6.4 \times 10^{4}$ Bq. Exactly 12 min later, the activity is $2.0 \times 10^{3} \mathrm{Bq} .$ Calculate the half-life of $^{108} \mathrm{Ag} .$
The activity of a sample containing radioactive ${ }^{108} \mathrm{Ag}$ is $6.4 \times 10^{4} \mathrm{Bq} .$ Precisely $12 \mathrm{min}$ later, the activity is $2.0 \times 10^{3} \mathrm{Bq} .$ Calculate the half-life of ${ }^{108} \mathrm{Ag}$
The initial activity of a radioactive sample is 120 Bq. If after 24 h the activity is measured to be 15 Bq, find the half-life of the sample.
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