The actual proportion of men who favor a certain tax proposal is $0.40$ and the corresponding proportion for women is $0.25 ; n_{1}=500 \mathrm{men}$ and $n_{2}=400$
women are interviewed at random, and their individual responses are looked upon as the values of independent random variables having Bernoulli distributions with the respective parameters $\theta_{1}=0.40$ and $\theta_{2}=0.25 .$ What can we assert, according to Chebyshev's theorem, with a probability of at least $0.9375$ about the value we will get for $\hat{\Theta}_{1}-\hat{\Theta}_{2}$, the difference between the two sample proportions of favorable responses? Use the result of Exercise 5 .