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The air within a piston equipped with a cylinder absorbs 565 J of heat and expands from an initial volume of 0.10 L to a final volume of 0.85 L against an external pressure of 1.0 atm. What is the change in internal energy of the air within the piston?

$$\begin{aligned} \Delta \mathrm{E} &=\mathrm{q}+\mathrm{w} \\ &=565 \mathrm{J}+(-76.0 \mathrm{J}) \\ &=489 \mathrm{J} \end{aligned}$$

02:45

Kevin C.

Chemistry 102

Chemistry 101

Chapter 9

Thermochemistry

Thermodynamics

Chemical reactions and Stoichiometry

Carleton College

Drexel University

Brown University

University of Toronto

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in this podcast. We're going to be taking a look at the area of summer dynamics within chemistry. So it's quite a physical area, involves a fair amount of math, and we're going to be calculating the change in internal energy. So we've got our heat we've got our initial volume or final volume are external pressure. Eso We can calculate our Delta V change in volume final volume. Subtract initial volume that's equal to not 0.85 Subtract not 0.1. So we've got no 0.75 liters. That's just a small calculation that we need to do next. We know that we have work that is equal to negative p multiplied by Delta V. So we plug in our values. So we've got negative one atmosphere 1.0 atmosphere multiplied by 9.75 liters because we just calculated that. And so we have work equal to negative not 0.7 five liters per atmosphere. We convert some units multiplied by wanna juan 0.3 to 5 jewels that's divided by 1.0 liters per atmosphere. We get back in jewels now that is negative. 76.0 jewels. Now, using this body. We can determine our change and energy. That is. Q. Uh, W So we have 565 jewels. Add negative 76.0 jewels. So are changing. Energy is 489 jewels.

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