00:01
Hi.
00:02
In the given problem we have been given an amometer which requires a current of 1 .50 millie ampere to give it a full scale deflection.
00:16
This is the maximum range of the current which can be measured with its help.
00:21
And the internal resistance of the amometer is 75 .0 ampere.
00:30
Um internal resistance of the amometer.
00:34
Now in the first part of the problem we want to increase the range of this amometer so that it may be able to measure up to 15 ampere for which we will have to apply ascent resistance in parallel with this ammeter.
00:56
The circuit diagram, the arrangement which we have to draw in the first part of the problem is such that this is the amometer, the original ammometer, this is its internal resistance.
01:11
Now if you want to increase its range but the maximum current which can pass through it is just 1 .50 millamper.
01:20
So in order to increase its range, we may bypass the extra current.
01:26
Current through it.
01:29
And in order to bypass that extra current, we apply a shun resistance in its parallel, which should be having a very low value so that more and more current may pass through it.
01:46
If the current entering into this arrangement is i, then the current passing through the ammeter coil should be ig only because it cannot tolerate...