Question
The amplitude of the electric field in a parallel beam of light of intensity $2.0 \mathrm{Wm}^{-2}$ is(A) $38.8 \mathrm{NC}^{-1}$(B) $19.4 \mathrm{NC}^{-1}$(C) $9.7 \mathrm{NC}^{-1}$(D) None of these.
Step 1
Step 1: The intensity (I) of a wave is given by the formula: \[I = \frac{1}{2} \varepsilon_0 c E^2\] where \(\varepsilon_0\) is the permittivity of free space, c is the speed of light, and E is the amplitude of the electric field. Show more…
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