00:01
This problem is asking us to react for athoxyanolin with acetic anhydride to form a compound called fanacetin.
00:10
So to start off, we're going to figure out what is our nucleophile and what is our electrophile.
00:15
So our nucleophile is going to be this nh2 right here that is the strongest nucleophile we have in this problem.
00:23
And our electrophile will be this anhydride.
00:27
So nucleophile is going to come in and attack the carbonyl carpentine.
00:31
On the anhydride and kick up that pie bond onto the o.
00:37
This will give us an intermediate that looks like this.
00:41
We'll have our o up here and our nh2 connected to the rest of that compound over there.
00:52
And now this end will be positive because we've added a bond to it.
01:00
But in the end, we don't want our product to have that positive charge on it.
01:03
We want it to be neutral, and we also need to help out our leaving group a little bit here...