Question
The angle of intersection of the circles $x^{2}+y^{2}+2 a x=0$ and $x^{2}+y^{2}+2 b y=0$ at $(0,0)$ is(a) $\frac{\pi}{3}$(b) $\frac{\pi}{4}$(c) 0(d) $\frac{\pi}{2}$
Step 1
The center of the first circle is $(-a, 0)$ and the center of the second circle is $(0, -b)$. Show more…
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The Tangent and Normal
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