Question
The angles of dip at two places are $30^{\circ}$ and $45^{\circ}$. The ratio of horizontal components of earth's magnetic field at the two places will be(a) $\sqrt{3}: \sqrt{2}$(b) $1: \sqrt{2}$(c) $1: 2$(d) $1: \sqrt{3}$
Step 1
The horizontal component of the Earth's magnetic field (Bh) is related to the total magnetic field (B) and the angle of dip (δ) by the formula: Bh = B * cos(δ) Show more…
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The real angle of dip, if a magnet is suspended at an angle of $30^{\circ}$ to the magnetic meridian and the dip needle makes an angle of $45^{\circ}$ with horizontal, is : (a) $\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)$ (b) $\tan ^{-1}(\sqrt{3})$ (c) $\tan ^{-1}\left(\frac{\sqrt{3}}{\sqrt{2}}\right)$ (d) $\tan ^{-1}\left(\frac{2}{\sqrt{3}}\right)$
In a certain place, the horizontal component of magnetic field is $\frac{1}{\sqrt{3}}$ times the vertical component. The angle of dip at this place is (a) zero (b) $\pi / 3$ (c) $\pi / 2$ (d) $\pi / 6$
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Round 2
At a certain place, the horizontal component of the earth's magnetic field is $B_{0}$ and the angle of dip is $45^{\circ}$. The total intensity of the field at that place will be (a) $B_{0}$ (b) $\sqrt{2} B_{0}$ (c) $2 B_{0}$ (d) $B_{0}^{1}$
Round 1
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