00:01
Okay, so this question is about the procession of the earth.
00:05
And so we are thinking of the earth as a gyroscope, and our goal is to get the torque needed to cause the earth to process.
00:16
So let's get down the givens, and then we can discuss how to do the problem.
00:21
I bet i'm going to have to look some givens up.
00:23
But first, let's write down the period is 2 .58 times 10 of the.
00:30
Four years.
00:43
And omega -p is torque over l.
00:46
I'll just put that there.
00:52
And our goal is to get the torque.
01:05
So if we know the period, then we know the procession frequency because this is 2 pi over this.
01:13
So we're looking for torque.
01:15
So that means what's left is l.
01:18
So we need the angular momentum of the earth.
01:21
If we model the earth as a sphere, we can say that l is equal to i, omega.
01:30
And then i, we can say, is two -fifths mr squared.
01:37
And so, and then we can say omega.
01:40
Let's write that in terms of the period.
01:42
So every day the earth makes one rotation.
01:48
And so it takes 24 hours to do that.
01:54
Ooh, i wonder if we could not have to translate everything into seconds.
01:58
I think we could get away with that.
02:02
So, yeah, i think we can.
02:05
So i'm going to try it.
02:08
But of course, to do this, we need the mass of the earth and then the radius of the earth.
02:13
So i'm going to look those up.
02:14
I think i actually almost remember them.
02:16
I think, and i'm going to write it down.
02:18
I think the mass of the earth is 5 .97.
02:22
I don't remember the exponent.
02:27
5 .97 times 10 to the 24.
02:30
Oh, like 24 hours in a day.
02:32
Good way to remember it.
02:39
And the radius, i think, has 6 .26.
02:44
Let's find out.
02:48
Oh, no.
02:50
It's 6 .37 times 10 to the 6 .6.
02:58
Close.
03:05
Meters.
03:06
Okay.
03:08
And then, so let's kind of, rearrange this and get it all neatly written...