Question
The anion $\mathrm{C}\left(\mathrm{NO}_{2}\right)_{3}$ - has a trigonal planar geometry about the carbon atom. Draw Lewis structures for $\mathrm{C}\left(\mathrm{NO}_{2}\right)_{3}^{-}$ including resonance forms, and determine which structure contributes the most to the bonding.
Step 1
Carbon has 4 valence electrons, nitrogen has 5, and oxygen has 6. Since there are 3 nitrogen atoms and 6 oxygen atoms, and the molecule carries a negative charge, the total number of valence electrons is $4 + 3(5) + 6(6) + 1 = 56$. Show more…
Show all steps
Your feedback will help us improve your experience
David Collins and 63 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The anion $\mathrm{C}(\mathrm{CN})_{3}$. has a trigonal planar geometry about the central carbon atom. Draw Lewis structures for $\mathrm{C}(\mathrm{CN})_{3}^{-},$ including resonance forms, and determine which structure contributes the most to the bonding.
Consider the $\mathrm{SC}\left[\mathrm{N}\left(\mathrm{CH}_{3}\right)_{2}\right]_{2}$ molecule in which $\mathrm{S}$ is bonded to $\mathrm{C}$ and each $\mathrm{CH}_{3}$ group is bonded to $\mathrm{N}$. Use Lewis structures and formal charges to write resonance structures and to determine which is the most plausible resonance structure.
Draw Lewis structures for the following and use the geometry predicted by the VSEPR model to determine what kind of hybrid orbitals the central atom uses in bond formation: (a) $\mathrm{ClO}_{3}^{-},(\mathbf{b}) \mathrm{SO}_{3},$ and $(\mathbf{c}) \mathrm{OF}_{2}$.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD