Problem

The application problems that follow may involve …

Question

Answered step-by-step

Problem 78 Easy Difficulty

The application problems that follow may involve more than merely division. Some may require addition, subtraction, or multiplication, whereas others may use a combination of two or more operations.
Filling Glasses How many 8-ounce glasses can be filled from three 32 -ounce bottles of soda?

Video Answer

Solved by verified expert

Textbook Answer

Official textbook answer

Video by Ankit Gupta

Numerade Educator

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Related Courses

No Related Courses

Prealgebra

Chapter 1

Whole Numbers

Section 6

Division with Whole Numbers

Discussion

You must be signed in to discuss.

Top Educators

Watch More Solved Questions in Chapter 1

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Problem 55

Problem 56

Problem 57

Problem 58

Problem 59

Problem 60

Problem 61

Problem 62

Problem 63

Problem 64

Problem 65

Problem 66

Problem 67

Problem 68

Problem 69

Problem 70

Problem 71

Problem 72

Problem 73

Problem 74

Problem 75

Problem 76

Problem 77

Problem 78

Problem 79

Problem 80

Problem 81

Problem 82

Problem 83

Problem 84

Problem 85

Problem 86

Video Transcript

Let beneath the x holds of water with the purity of 0 percent as absolute water has. A purity of 0 percent of its kind, so 20 pose, is available with the percentage of a and we need a 20 plus x liter of solution with a percentage of 2. Hence applying the formula of percentage we take as 0 percent of x plus 8 percent of 20 is equal to 2 percent of 20 plus x, so 0, upon 100 multiplied by x, plus 500. Multiplied by 20 is equal to 2, upon 100 multiplied by 20 plus x, so 0 plus 116 is equal to 14. Plus 2 is so we get it, as were a 60 water, to get a solution of 2 percent with a quantity of 81. So this is the answer of the question.

Get More Help with this Textbook

Charles P. McKeague

Prealgebra

View More Answers From This Book

Find Another Textbook

Study Groups

Study with other students and unlock Numerade solutions for free.

Problem