Problem 9 Easy Difficulty

The approximate change in the volume of a cube of side $x$ metres caused by increasing the side by $3 \%$ is
(A) $0.06 x^{3} \mathrm{~m}^{3}$
(B) $0.6 x^{3} \mathrm{~m}^{3}$
(C) $0.09 x^{3} \mathrm{~m}^{3}$
(D) $0.9 x^{3} \mathrm{~m}^{3}$

Answer

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Video Transcript

the questions is the approximate changing the volume of a cube of side X meters caused by increasing decided by 3% Party .06 X cube meter cube B S .6 Excuse Me Take You CS .09 Xq meter Cube and DS .9 Xq meter cubed. So now moving towards the solution and the answer to this question would be the part C, which is .09. Excuse me. Thank you. Now see the explanation as we know that the volume is given by X cube. So D V by dx will be called to three X square. Let it be the question too. And it will be the question one. Now as there is an increase of 3% so it can be written as three years by 100 and Dell X will be equal to three X by 100. Now since the approximate change in the volume of a cube. Well given by Dell the D V. And so it will be equal to D V by dx N two TX. That can be returned to us, DV by TX into Delta X. And so solving this after putting the values, you will get the task approximately equal 2.09. Excuse me to Q. Thank you.

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