The area, $A,$ of a triangle is $A=\frac{1}{2} b h,$ where $b=$ length of the base and $h=$ height.
The area, $A,$ of a triangle is $A=\frac{1}{2} b h,$ where $b=$ length of the base and $h=$ height.
a) Solve $A=\frac{1}{2} b h$ for $h$
b) Find the height of the triangle that has an area of 30 in $^{2}$ and a base of length 12 in.