Question
The area of cross-section of a steel wire is $\left[\mathrm{Y}=2 \times 10^{11}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\right]$ is $0.1 \mathrm{~cm}^{2}$, what will be the forcerequired to double its length ?(A) $2 \times 10^{12} \mathrm{~N}$(B) $2 \times 10^{11} \mathrm{~N}$(C) $2 \times 10^{10} \mathrm{~N}$(D) $2 \times 10^{6} \mathrm{~N}$
Step 1
In this case, the length of the wire is doubled, so $\Delta L = L$. Therefore, the strain is $\frac{L}{L} = 1$. Show more…
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