The coordinates of the vertices of the triangle are given as $A(2,0)$, $B(4,5)$ and $C(6,3)$.
The equation of line AB is given by $y - 0 = \frac{5}{2}(x - 2)$, which simplifies to $y = \frac{5}{2}x - 5$.
The equation of line BC is given by $y - 5 =
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