00:01
All right, so this problem is a really interesting application of bay theorem because it deals with overlapping events in a way.
00:06
So firstly, let's define a couple of events.
00:09
We're talking about whether eggs are broken or not in a carton.
00:13
So let's define event a as non -broken.
00:16
All right, let's define event b as one, say exactly one broken.
00:25
And then c and d will be two and three broken respectively.
00:28
So c will be exactly two broken.
00:30
And you'll see why the exactly is important in just a sec.
00:36
And we're told that the probability that exactly four are broken or more is negligible.
00:43
All right.
00:44
So we're also given associated probabilities for these, right? we're given that the probability of a, we're given that the probability of a is 0 .75, given that the probability of b is 0 .192.
01:01
Let me put an equal sign there.
01:03
Probability of c is equal to 0 .022, that's 2 .2%.
01:08
And the probability of d is equal to 0 .001, or rather 0 .1%.
01:16
Now we are asked, and this is often the tricky part of the question.
01:22
We are told that an egg is selected at random from a carton, and it is found to be broken.
01:27
So there is a broken egg.
01:28
I'm literally going to type that.
01:30
There is a broken egg.
01:33
And we are asked, what is the probability that this egg is the only one broken? so firstly, we want, what is the probability that there is exactly one broken egg given that you are holding in your hand a broken egg? okay, so given that there is at least one broken.
01:56
We know that.
01:57
We're holding it...