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Problem 1 Easy Difficulty

The atomic mass of $\mathrm{Cl}$ is 35.45 amu, and the atomic mass of Al is 26.98 amu. What are the masses in grams of 3 $\mathrm{mol}$ of $\mathrm{Al}$ atoms and of 2 $\mathrm{mol}$ of $\mathrm{Cl}$ atoms?

Answer

$\operatorname{Ar}(\mathrm{Al})=26,98$ amu
$\mathrm{n}(\mathrm{Al})=3 \mathrm{mol}$
$\mathrm{m}=\mathrm{n}^{*} \mathrm{Ar}(\mathrm{Al})=26.98 \mathrm{g} / \mathrm{mol} * 3 \mathrm{mol}=80,94 \mathrm{g}$
$\operatorname{Ar}(\mathrm{Cl})=35,45 \mathrm{amu}$
$\mathrm{n}(\mathrm{Cl})=2 \mathrm{mol}$
$\mathrm{m}=\mathrm{n}^{*} \mathrm{Ar}(\mathrm{Cl})=35,45 \mathrm{g} / \mathrm{mol} * 2 \mathrm{mol}=70,9 \mathrm{g}$

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Video Transcript

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University of Toronto
Top Chemistry 101 Educators
Stephanie C.

University of Central Florida

Lizabeth T.

Numerade Educator

Nadia L.

Rice University

Allea C.

University of Maryland - University College