Question
The atomic weight, density, and atomic radius for three hypothetical alloys are listed in the following table. For each, determine whether its crystal structure is FCC, BCC, or simple cubic and then justify your determination.
Step 1
The formula is given by: \[ \rho = \frac{nA}{V_{\text{cell}}N_{\text{A}}} \] where $\rho$ is the density, $n$ is the number of atoms per unit cell, $A$ is the atomic weight, $V_{\text{cell}}$ is the volume of the unit cell, and $N_{\text{A}}$ is Avogadro's Show more…
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Below are listed the atomic weight, density, and atomic radius for three hypothetical alloys. For each determine whether its crystal structure is FCC, BCC, or simple cubic and then justify your determination. A simple cubic unit cell is shown in Figure 3.23 $$\begin{array}{lccc} \hline & \text {Atomic} & & \text {Atomic} \\ & \text {Weight} & \text {Density} & \text {Radius} \\ \text {Alloy} & \text { (g/mol) } & \left(\mathrm{g} / \mathrm{cm}^{3}\right) & (\boldsymbol{n m}) \\ \hline \mathrm{A} & 43.1 & 6.40 & 0.122 \\ \mathrm{B} & 184.4 & 12.30 & 0.146 \\ \mathrm{C} & 91.6 & 9.60 & 0.137 \\ \hline \end{array}$$
3. The atomic weight, density, and atomic radius for three hypothetical alloys are listed in the following table. For each, determine whether its crystal structure is FCC, BCC, or simple cubic. Show your work. Alloy amu (g/mol) 43.1 84.4 91.6 Density (g/cmÂł) 12.2 14.6 13.7 Radius (nm) 0.122 0.146 0.137
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