00:01
So they collected data on pairs of fridays in a month, the 6th and the 13th, and they're comparing those together to see about the number of people that are admitted to the hospital on those.
00:19
They're pairs of fridays of the month, so we can use a paired t -test for this.
00:27
Now for our null hypothesis, 6 is 1 and the 13th would be 2.
00:37
We're gonna do subtract those and if there's no difference between them, that would be that it was 0 and h -a more people are admitted on friday the 13th.
00:57
So if we have more people admitted on friday the 13th, that means that we're gonna get negative numbers.
01:04
It's important to have these sketched out so that you can draw your conclusion.
01:11
Well, my p -value is 0 .0211.
01:17
So since that p -value is smaller than 0 .05, we can reject the null hypothesis.
01:30
This means there is convincing evidence or enough evidence or whatever that more people are admitted to the hospital on friday the 13th.
02:10
Okay, because the p -value is smaller than 0 .05, we're gonna reject that they're the same and there's enough evidence to say that the mean number of people admitted to the hospitals on friday the 13th is larger than other days, other fridays.
02:29
And then c wants us to check out the conditions.
02:33
We need to ask ourselves, were the days, the pairs, picked randomly? we don't know.
03:00
So this kind of makes it on sketchy ground because it doesn't say anything about the pairs of dates being selected at random.
03:18
Yeah, so that's kind of sketchy...