Question
The auxiliary circle of the ellipse $\frac{x^{2}}{9}+\frac{y^{2}}{16}=1$ is(a) $x^{2}+y^{2}=25$(b) $x^{2}+y^{2}=16$(c) $x^{2}+y^{2}=9$(d) $x^{2}+y^{2}=4$
Step 1
From this equation, we can see that the semi-major axis is $a=4$ and the semi-minor axis is $b=3$. Show more…
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The ellipse $4 x^{2}+8 y^{2}=64$ and the circle $x^{2}+y^{2}=9$ intersect at points where the $y$ -coordinate is (A) $\pm \sqrt{2}$ (B) $\pm \sqrt{5}$ (C) $\pm \sqrt{6}$ (D) $\pm \sqrt{7}$ (E) $\pm 10.00$
(a) The auxiliary circle of an ellipse is defined to be the circle with diameter the same as the major axis of the ellipse. Determine the equation of the auxiliary circle for the ellipse $9 x^{2}+25 y^{2}=225$ (b) Graph the ellipse $9 x^{2}+25 y^{2}=225$ along with its auxiliary circle. (Use true proportions.)
(a) The auxiliary circle of an ellipse is defined to be the circle with diameter the same as the major axis of the ellipse. Determine the equation of the auxiliary circle for the ellipse $9 x^{2}+25 y^{2}=225$. (b) Graph the ellipse $9 x^{2}+25 y^{2}=225$ along with its auxiliary circle. (Use true proportions.)
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