00:02
For our problem, we're given that the average commute is 25 minutes and the standard deviation is 6 .1 minutes.
00:09
We first need to find the probability that a commute is greater than 30 minutes.
00:14
So we are going to start by changing our value of 30 minutes to its z score or z value using our formula, z equals the value minus the mean over or divided by the standard deviation.
00:30
So 30 minus 25 divided by 6 .1.
00:39
And this comes out to be approximately 0 .82.
00:45
We're going to round to two decimal places here because our standard normal distribution table goes to two decimal places for our z scores.
00:54
So we are finding the probability that the z score or z value is greater than 0 .82.
01:08
Now if we're to draw a sketch of what this would look like, we would draw our standard normal distribution.
01:17
The mean would be 0, and then we'd have one standard deviation away, two, standard deviations away, three, and you can also go in the other direction.
01:31
Our z value is going to be, is 0 .82, so we're going to sketch the approximate.
01:38
Here and we're looking for the probability that it's greater than that so the area to the right will give us the probability that it's greater than 0 .82.
01:50
Now our standard normal distribution table gives us the area under the curve to the left of a z score so since we're trying to find the area to the right we need to do one minus the value we're given in the table.
02:05
So if we go to our table and we look up the z score 0 .82, we're going to see the value .7939.
02:19
And we do one minus that value to give us the probability or area to the right.
02:24
So that's going to be 0 .2061.
02:30
Or we can write it as a percent...