The average time it takes for a molecule to diffuse a distance of x cm is given by t=(x^2)/(2 D

step 1 In this problem, we have to calculate the time taken by a glucose molecules to diffuse equal in

The average time it takes for a molecule to diffuse a...

The average time it takes for a molecule to diffuse a distance of $x \mathrm{~cm}$ is given by $$ t=\frac{x^2}{2 D} $$ where $t$ is the time in seconds and $D$ is the diffusion coefficient. Given that the diffusion coefficient of glucose is $5.7 \times 10^{-7} \mathrm{~cm}^2 / \mathrm{s}$, calculate the time it would take for a glucose molecule to diffuse $10 \mu \mathrm{~m}$, which is roughly the size of a cell.

The average time it takes for a molecule to diffuse a distance of $x \mathrm{~cm}$ is given by

$$
t=\frac{x^2}{2 D}
$$

where $t$ is the time in seconds and $D$ is the diffusion coefficient. Given that the diffusion coefficient of glucose is $5.7 \times 10^{-7} \mathrm{~cm}^2 / \mathrm{s}$, calculate the time it would take for a glucose molecule to diffuse $10 \mu \mathrm{~m}$, which is roughly the size of a cell.

The average time taken for a molecule or an organelle to diffuse a distance of $x \mathrm{cm}$ is given by the formula \[t=x^{2} / 2 D\] where $t$ is the time in seconds and $D$ is a constant called the diffusion coefficient for the molecule or particle. Using the above formula, calculate the time it would take for a small molecule, a protein, and a membrane vesicle to diffuse from one side to another of a cell $10 \mu \mathrm{m}$ across. Typical diffusion coefficients in units of $\mathrm{cm}^{2} / \mathrm{sec}$ are: small molecule, $5 \times 10^{-6}$ protein molecule, $5 \times 10^{-7} ;$ vesicle, $5 \times 10^{-8}$. How long would a membrane vesicle take to reach the end of an axon $10 \mathrm{cm}$ long by free diffusion? How long would it take if it was transported along microtubules at $1 \mu \mathrm{m} / \mathrm{sec} ?$

Please give Ace some feedback