00:01
So they want us to draw at least three resident structures of isidobenzene.
00:12
And be sure to include all of the formal charges to all of our atoms.
00:21
All right.
00:21
So they want us to draw three in addition to this.
00:23
And they also talk about what the azide is.
00:26
So the azide is this group right here on the end.
00:32
It's these three nitrogen's kind of all linked together.
00:37
Now, let's go ahead and see what kind of resonance we could do.
00:43
Actually, before we do that, let's put our former charges down.
00:45
So you might recall that carbon normally has four bonds to it, and nitrogen normally has three.
00:56
All right.
00:57
And the nitrogen also normally has one lone pair on it.
01:01
I should say that.
01:02
So let's go ahead and see which kind of differ from this.
01:04
So all the carbons are going to have four bonds, because remember we have to account for the hydrogens that are there.
01:15
This first nitrogen is going to have two bonds and two loan pairs.
01:21
So this actually lost a bond, but it gained a lone pair.
01:25
So that means this nitrogen is going to have a negative charge on it.
01:28
Our next nitrogen here has four bonds, but it lost a lone pair.
01:32
So that means it's going to be positively charged.
01:35
And then our nitrogen on the end here, it has three bonds and one lone pair.
01:38
So that would be neutrally charged.
01:40
So that seems good.
01:41
Now let's see what kind of resident structures we can come up with.
01:47
One we could do is just move all of our double bonds around on our ring.
01:52
So that's a pretty straightforward one.
01:54
So just move this here...