The benzylammonium ion $\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{NH}_{3}^{+}\right)$ has $\mathrm{pK}_{\mathrm{a}}=9.33,$ and the propyl-ammonium ion has $\mathrm{pK}_{\mathrm{a}}=10.71$. Which is the stronger base, benzylamine or propylamine? What are the $\mathrm{pK}_{\mathrm{b}}$ 's of benzylamine and propylamine?